The construction of a $Δ A B C$ in which $B C = 6$ $c m$ and $∠ B = 50^{\circ}$ , is not possible when $(A B - A C)$ is equal to:

5.6 c m

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5 c m

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6 c m

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4.8 c m

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Solution

The correct option is C $6 c m$
For construction of triangle sum of any two sides must be greater then third side
$\Rightarrow A C + B C > A B$
$A C + 6 > A B$
$6 > A B - A C$
$A B - A C < 6$
So $A B - A C \neg 6$
Option $C$ is correct.

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Similar questions

Q. The construction of a ∆ABC in which BC = 6 cm and ∠B = 50° is not possible when (AB − AC) is equal to
(a) 5.6 cm
(b) 5 cm
(c) 6 cm
(d) 4.8 cm

Q. The construction of a ∆ABC in which AB = 6 cm, ∠A = 45° is possible when (BC + AC) is
(a) 7 cm
(b) 5.8 cm
(c) 5 cm
(d) 4.9 cm

$In each of the following cases,given reasons to show that the construction of Δ A B C i s n o t p o s s i b l e : (i) A B = 6 c m, ∠ A = 40^{\circ} a n d (B C + A C) = 5.58 c m (i i) A B = 7 c m, ∠ A = 50^{\circ} a n d (B C - A C) = 8 c m (i i i) B C = 5 c m, ∠ B = 80^{\circ}, ∠ C = 50^{\circ}, a n d ∠ A = 60^{\circ} (i v) A B = 4 c m, B C = 3 c m, a n d A C = 7 c m .$

Q. Construct a Δ ABC in which AB + AC = 5.6 cm, BC = 4.5 cm and ∠B = 45°.

Q. The construction of

Δ A B C

, given that BC = 6cm,

∠ B = 45^{\circ}

is not possible when the difference between AC and AB is equal to

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The construction of a ΔABC in which BC=6 cm and ∠B=50∘, is not possible when (AB−AC) is equal to:

The correct option is C 6 cmFor construction of triangle sum of any two sides must be greater then third side⇒AC+BC>ABAC+6>AB6>AB−ACAB−AC<6So AB−AC¬6Option C is correct.

The construction of a $Δ A B C$ in which $B C = 6$ $c m$ and $∠ B = 50^{\circ}$ , is not possible when $(A B - A C)$ is equal to:

The correct option is C $6 c m$
For construction of triangle sum of any two sides must be greater then third side
$\Rightarrow A C + B C > A B$
$A C + 6 > A B$
$6 > A B - A C$
$A B - A C < 6$
So $A B - A C \neg 6$
Option $C$ is correct.