The coordinates of a point on the line x−12=y+1−3 at a distance 4√14 from the point (1, -1, 0)nearer the origin are
A
(9,−13,−4)
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B
(8√14,−12,−1)
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C
(−8√14,−12,1)
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D
(−7,11,−4)
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Solution
The correct option is D(−7,11,−4) Any point on given line is (2r +1, - 3r – 1, r), its distance from (1, -1, 0). ⇒(2r)2+(−3r)2+r2=(4√14)2⇒r=±4 ⇒ Coordinates are (9, -13, 4)and (-7, 11, -4) and nearer to the origin is (-7, 11, -4).