The coordinates of moving particle at time t are given by $x = c t^{2} a n d y = b t^{2}$ . The speed of the particle is given by

2 t (c + b)

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2 t \sqrt{c^{2} - b^{2}}

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t \sqrt{c^{2} + b^{2}}

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2 t \sqrt{c^{2} + b^{2}}

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Solution

The correct option is C $2 t \sqrt{c^{2} + b^{2}}$
velocity in x -axis direction $v_{x} = \frac{d x}{d t} = 2 c t$
in y direction $v_{y} = \frac{d y}{d t} = 2 b t$
therefore velocity is $v = \sqrt{v_{x}^{2} + v_{y}^{2}} = 2 t \sqrt{c^{2} + b^{2}}$

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Similar questions

The coordinates of a moving particle at any time are given by $x = a t^{2}$ and $y = b t^{2}$ . The speed of the particle at any moment is

t

x = c t^{2}

y = b t^{2}

t

x = c t^{2}

y = b t^{2}

\frac{a^{2} - {(b - c)}^{2}}{{(a + c)}^{2} - b^{2}} + \frac{b^{2} - {(a - c)}^{2}}{{(a + b)}^{2} - c^{2}} + \frac{c^{2} - {(a - b)}^{2}}{{(b + c)}^{2} - a^{2}}

a, b, c

a^{2} = b^{2} + c^{2} - 2 b c \sqrt{1 - a^{2}}, b^{2} = c^{2} + a^{2} - 2 c a \sqrt{1 - b^{2}}, c^{2} = a^{2} + b^{2} - 2 a b \sqrt{1 - c^{2}}

a = c \sqrt{1 - b^{2}} + b \sqrt{1 - c^{2}}

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