CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

The core of a toroid having 3000 turns has inner and outer radial 11 cm and 12 cm respectively. The magnetic field in the core for a current of 0.7 A is 2.5 T. Calculate the relative permeability of the core ?

A
684
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
290
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
395
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
768
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 684
Given:
N=3000; r1=11 cm; r2=12 cm
i=0.7 A and B=2.5 T

So the mean radius of toroid will be

r=r1+r22=11.5 cm=11.5×102 m

Magnetic field produced by toroid inside the core of toroid is given by

B=μ0μrNi2πr

2.5=4π×107×μr×3000×0.72π×11.5×102

μr=2.5×2π×11.5×1024π×107×3000×0.7

μr684

Hence, option (a) is correct.
Why this question ?
Concept :
Magnetic field, B=μni
Here, μ=μ0μr

flag
Suggest Corrections
thumbs-up
3
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon