The correct graph representing the variation of total energy $(E_{t})$ kinetic energy $(E_{k})$ and potential energy (U) of a satellite with its distance from the centre of earth is

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Solution

The correct option is C
$U = \frac{- G M m}{r}, K = \frac{G M m}{2 r} a n d E = \frac{- G M m}{2 r}$
For a satellite U, K and E varies with r and also U and E remains negative whereas K remain always positive.

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The correct option is C
$U = \frac{- G M m}{r}, K = \frac{G M m}{2 r} a n d E = \frac{- G M m}{2 r}$
For a satellite U, K and E varies with r and also U and E remains negative whereas K remain always positive.