Question

The correct increasing order of stability of the following free radicals is

• A. $(C{H}_3{)}_2\stackrel{.}{C}H<C_6{H}_5\stackrel{.}{C}{H}_2<(C{H}_3{)}_3\stackrel{.}{C}<(C_6{H}_5{)}_2\stackrel{.}{C}H$
• B. $(C{H}_3{)}_2\stackrel{.}{C}H<(C{H}_3{)}_3\stackrel{.}{C}<\left(C_6{H}_5\right)\stackrel{.}{C}{H}_2<(C_6{H}_5{)}_2\stackrel{.}{C}H$
• C. $(C{H}_3{)}_3\stackrel{.}{C}<(C{H}_3{)}_2\stackrel{.}{C}H<\left(C_6{H}_5\right)\stackrel{.}{C}{H}_2<(C_6{H}_5{)}_2\stackrel{.}{C}H$
• D. $C_6{H}_5\stackrel{.}{C}{H}_2<(C_6{H}_5{)}_2\stackrel{.}{C}H<(C{H}_3{)}_2\stackrel{.}{C}<(C{H}_3{)}_3\stackrel{.}{C}$

Answer 1

The correct option is B

$(C{H}_3{)}_2\stackrel{.}{C}H<(C{H}_3{)}_3\stackrel{.}{C}<\left(C_6{H}_5\right)\stackrel{.}{C}{H}_2<(C_6{H}_5{)}_2\stackrel{.}{C}H$

More the number of phenyl groups more is the stability due to resonance.