The correct option is C Tetraammine dichloro platinum (IV) tetrachloro platinate (II)
The compound has cationic and anionic parts as follows:
[Pt(NH3)4Cl2]2+[PtCl4]2−
First naming of cationic part is done and then anionic part. So, the name of the compound is:
Tetraammine dichloro platinum (IV) tetrachloro platinate (II)