Question

The correct order for the boiling point between $CC{l}_4$ and $SiC{l}_4$ is:

• A. $CC{l}_4>SiC{l}_4$
• B. $SiC{l}_4>CC{l}_4$
• C. $SiC{l}_4=CC{l}_4$
• D. None of these

Answer 1

Answer: (A)

$CC{l}_4>SiC{l}_4$

The magnitude of negative charge developed at chlorine atoms in $SiC{l}_4$ is more in comparison to negative charge developed at chlorine atoms in $CC{l}_4$, it is due to more electronegativity difference between $Si$ and $Cl$ than that of between $C$ and $Cl$.

The boiling point of $CC{l}_4$ is $76.72$${}^{0}C$ whereas the boiling point of $SiC{l}_4$ is $57.65$${}^{0}C$. Thus, the correct order for the boiling point is $CC{l}_4>SiC{l}_4$.