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Valency and Oxidation State

The correct o...

Question

The correct order of acidic nature is:

A

H C l O_{4} > H_{2} {S O}_{4} > H_{3} {P O}_{4}

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B

H C l O_{4} > H_{3} {P O}_{4} > H_{2} {S O}_{4}

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C

H_{2} {S O}_{4} > H C l O_{4} > H_{3} {P O}_{4}

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D

H_{2} {S O}_{4} > H_{3} {P O}_{4} > H C l O_{4}

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Solution

The correct option is B $H C l O_{4} > H_{2} {S O}_{4} > H_{3} {P O}_{4}$
Acidic character increases along the period and as oxidation state increases, acidic nature increases.
So order is :
$H C l O_{4} > H_{2} S O_{4} > H_{3} P O_{4}$
$+ 7$ $+ 6$ $+ 5$

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Q. The total number of diprotic acids among the following is:

H_{3} {P O}_{4}, H_{2} {S O}_{4}, H_{3} {P O}_{3}, H_{2} {C O}_{3}, H_{2} S_{2} O_{7}, H_{3} B O_{3}, H_{3} {P O}_{2}, H_{2} {C r O}_{4}, H_{2} {S O}_{3}

H_{2} {S O}_{4}

H_{3} {P O}_{4}

are neutralized separately by the same amount of an alkali when sulphate and dihydrogen phosphates are formed respectively.Find the ratio of the masses of

H_{2} {S O}_{4}

H_{3} {P O}_{4}

H_{2} {S O}_{4}

H_{3} {P O}_{4}

are neutralized separately by the same amount of an alkali when sulphate and dihydrogen orthophosphate are formed, respectively. Find the ratio of the masses of

H_{2} {S O}_{4}

H_{3} {P O}_{4}

Q. Three reactions involving

H_{2} {P O}_{4}^{-}

are given below:
(i)

H_{3} {P O}_{4} + H_{2} O \to H_{3} O^{+} + H_{2} {P O}_{4}^{-}

H_{2} {P O}_{4}^{-} + H_{2} O \to H {P O}_{4}^{2 -} + H_{3} O^{+}

H_{2} {P O}_{4}^{-} + {O H}^{-} \to H_{3} {P O}_{4} + O^{2 -}

H_{2} O + H_{3} {P O}_{4} ⇌ H_{3} O^{+} + H_{2} {P O}_{4}^{-}; p K_{1} = 2.15

H_{2} O + H_{2} {P O}_{4}^{-} ⇌ H_{3} O^{+} + H_{2} {P O}_{4}^{2 -}; p K_{2} = 7.20

0.01 M

N a H_{2} {P O}_{4}

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