CameraIcon

SearchIcon

MyQuestionIcon

21

You visited us 21 times! Enjoying our articles? Unlock Full Access!

Valency and Oxidation State

The correct o...

Question

The correct order of acidic nature is:

A

H C l O_{4} > H_{2} {S O}_{4} > H_{3} {P O}_{4}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

B

H C l O_{4} > H_{3} {P O}_{4} > H_{2} {S O}_{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

H_{2} {S O}_{4} > H C l O_{4} > H_{3} {P O}_{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

H_{2} {S O}_{4} > H_{3} {P O}_{4} > H C l O_{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $H C l O_{4} > H_{2} {S O}_{4} > H_{3} {P O}_{4}$
Acidic character increases along the period and as oxidation state increases, acidic nature increases.
So order is :
$H C l O_{4} > H_{2} S O_{4} > H_{3} P O_{4}$
$+ 7$ $+ 6$ $+ 5$

Suggest Corrections

thumbs-up

0

Similar questions

Q. The total number of diprotic acids among the following is:

H_{3} {P O}_{4}, H_{2} {S O}_{4}, H_{3} {P O}_{3}, H_{2} {C O}_{3}, H_{2} S_{2} O_{7}, H_{3} B O_{3}, H_{3} {P O}_{2}, H_{2} {C r O}_{4}, H_{2} {S O}_{3}

H_{2} {S O}_{4}

H_{3} {P O}_{4}

are neutralized separately by the same amount of an alkali when sulphate and dihydrogen phosphates are formed respectively.Find the ratio of the masses of

H_{2} {S O}_{4}

H_{3} {P O}_{4}

H_{2} {S O}_{4}

H_{3} {P O}_{4}

are neutralized separately by the same amount of an alkali when sulphate and dihydrogen orthophosphate are formed, respectively. Find the ratio of the masses of

H_{2} {S O}_{4}

H_{3} {P O}_{4}

Q. Three reactions involving

H_{2} {P O}_{4}^{-}

are given below:
(i)

H_{3} {P O}_{4} + H_{2} O \to H_{3} O^{+} + H_{2} {P O}_{4}^{-}

H_{2} {P O}_{4}^{-} + H_{2} O \to H {P O}_{4}^{2 -} + H_{3} O^{+}

H_{2} {P O}_{4}^{-} + {O H}^{-} \to H_{3} {P O}_{4} + O^{2 -}

H_{2} O + H_{3} {P O}_{4} ⇌ H_{3} O^{+} + H_{2} {P O}_{4}^{-}; p K_{1} = 2.15

H_{2} O + H_{2} {P O}_{4}^{-} ⇌ H_{3} O^{+} + H_{2} {P O}_{4}^{2 -}; p K_{2} = 7.20

0.01 M

N a H_{2} {P O}_{4}

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Oxidation Number and State

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Valency and Oxidation State

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon