Question

The correct order of acidic strength of oxyacids of chlorine is:

• A. $HClO<HCl{O}_2<HCl{O}_3<HCl{O}_4$
• B. $HCl{O}_4<HCl{O}_3<HCl{O}_2<HClO$
• C. $HClO>HCl{O}_4>HCl{O}_3>HCl{O}_2$
• D. $HCl{O}_4<HCl{O}_2>HCl{O}_3>HClO$

Answer 1

The correct option is A $HClO<HCl{O}_2<HCl{O}_3<HCl{O}_4$

In $HCl{O}_4$, oxidation number of $Cl$ is +7.

In $HCl{O}_3$, oxidation number of $Cl$ is +5.

In $HCl{O}_2$, oxidation number of $Cl$ is +3.

In $HCl{O}_1$, oxidation number of $Cl$ is +1.

Higher the positive oxidation number, higher is the electron deficiency, and higher is the acidic character. Lewis acids are electron acceptors.
So order is $HClO<HCl{O}_2<HCl{O}_3<HCl{O}_4$.