Question

# The correct order of acidity of oxoacids of halogens is:

A
HClO < HClO2 < HClO3 < HClO4
B
HClO4 < HClO3 < HClO2 < HClO
C
HClO < HClO4 < HClO3 < HClO2
D
HClO4 < HClO2 < HClO3 < HClO

Solution

## The correct option is B $$HClO$$ < $$HClO_{2}$$ < $$HClO_{3}$$ < $$HClO_{4}$$$$HClO\longrightarrow 1+x-2=0$$$$x=+1$$$$HClO_2\longrightarrow 1+x-4=0$$$$x=+3$$$$HClO_3\longrightarrow 1+x-6=0$$$$x=+5$$$$HClO_4\longrightarrow 1+x-8=0$$$$x=+7$$Higher is the oxidation state of the central atom higher is the acidity.Hence, the correct order of acidity : $$HClO_4$$ < $$HClO_3$$ < $$HClO_2$$ < $$HClO$$.Hence, the correct answer is option $$\text{A}$$.ChemistryNCERTStandard XII

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