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Question

The correct order of acidity of oxoacids of halogens is:


A
HClO < HClO2 < HClO3 < HClO4
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B
HClO4 < HClO3 < HClO2 < HClO
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C
HClO < HClO4 < HClO3 < HClO2
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D
HClO4 < HClO2 < HClO3 < HClO
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Solution

The correct option is B $$HClO$$ < $$HClO_{2}$$ < $$HClO_{3}$$ < $$HClO_{4}$$
$$HClO\longrightarrow 1+x-2=0$$
$$x=+1$$

$$HClO_2\longrightarrow 1+x-4=0$$
$$x=+3$$

$$HClO_3\longrightarrow 1+x-6=0$$
$$x=+5$$

$$HClO_4\longrightarrow 1+x-8=0$$
$$x=+7$$

Higher is the oxidation state of the central atom higher is the acidity.

Hence, the correct order of acidity : $$HClO_4$$ < $$HClO_3$$ < $$HClO_2$$ < $$HClO$$.

Hence, the correct answer is option $$\text{A}$$.

Chemistry
NCERT
Standard XII

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