Question

The correct order of acidity of oxoacids of halogens is:

• A. $HClO$ < $HCl{O}_2$ < $HCl{O}_3$ < $HCl{O}_4$
• B. $HCl{O}_4$ < $HCl{O}_3$ < $HCl{O}_2$ < $HClO$
• C. $HClO$ < $HCl{O}_4$ < $HCl{O}_3$ < $HCl{O}_2$
• D. $HCl{O}_4$ < $HCl{O}_2$ < $HCl{O}_3$ < $HClO$

Answer 1

Answer: (A)

$HClO$ < $HCl{O}_2$ < $HCl{O}_3$ < $HCl{O}_4$

$HClO⟶1+x-2=0$

$x=+1$

$HCl{O}_2⟶1+x-4=0$

$x=+3$

$HCl{O}_3⟶1+x-6=0$

$x=+5$

$HCl{O}_4⟶1+x-8=0$

$x=+7$

Higher is the oxidation state of the central atom higher is the acidity.

Hence, the correct order of acidity : $HCl{O}_4$ < $HCl{O}_3$ < $HCl{O}_2$ < $HClO$.

Hence, the correct answer is option $\text{A}$.