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Metallic Bond

The correct o...

Question

The correct order of boiling point of $K, C a, S c$ is:

A

K > C a > S c

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B

C a > K > S c

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C

S c > C a > K

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D

K > S c > C a

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Solution

The correct option is C $S c > C a > K$
As the number of mobile electrons increases, strength of metallic bonding increases and as a result boiling point also increases. The number of mobile electrons will be more in transition metal $(S c)$ than alkaline earth metal $(C a)$ than in alkali metal $(K)$ . Hence the correct order of boiling point is $S c > C a > K$ .

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