The correct order of boiling ponts of the following amines
$C_{4} H_{9} N H_{2}, (C_{2} H_{5})_{2} N H, C_{2} H_{5} N (C H_{3})_{2}$ is:

C_{2} H_{5} N (C H_{3})_{2} > (C_{2} H_{5})_{2} N H > C_{4} H_{9} N H_{2}

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(C_{2} H_{5})_{2} N H > C_{2} H_{5} N (C H_{3})_{2} > C_{4} H_{9} N H_{2}

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C_{4} H_{9} N H_{2} > (C_{2} H_{5})_{2} N H > C_{2} H_{5} N (C H_{3})_{2}

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(C_{2} H_{5})_{2} N H > C_{4} H_{9} N H_{2} > C_{2} H_{5} N (C H_{3})_{2}

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Solution

The correct option is C $C_{4} H_{9} N H_{2} > (C_{2} H_{5})_{2} N H > C_{2} H_{5} N (C H_{3})_{2}$
$C_{4} H_{9} N H_{2}$ is primary amine and can form hydrogen bond more than secondary amine $(C_{2} H_{5})_{2} N H$ and tertiary amine $C_{2} H_{5} N (C H_{3})_{2}$ . More hydrogen bonding leads to strong bonding between the molecules, hence boiling point increases in the order: Primary>Secondary>Tertiary
So, (c) is the correct option.

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Similar questions

C_{4} H_{9} N H_{2}, (C_{2} H_{5})_{2} N H, C_{2} H_{5} N (C H_{3})_{2}

Arrange the following:

(i) In decreasing order of the pK_bvalues:

C₂H₅NH₂, C₆H₅NHCH₃, (C₂H₅)₂NH and C₆H₅NH₂

(ii) In increasing order of basic strength:

C₆H₅NH₂, C₆H₅N(CH₃)₂, (C₂H₅)₂NH and CH₃NH₂

(iii) In increasing order of basic strength:

(a) Aniline, p-nitroaniline and p-toluidine

(b) C₆H₅NH₂, C₆H₅NHCH₃, C₆H₅CH₂NH₂.

(iv) In decreasing order of basic strength in gas phase:

C₂H₅NH₂, (C₂H₅)₂NH, (C₂H₅)₃N and NH₃

(v) In increasing order of boiling point:

C₂H₅OH, (CH₃)₂NH, C₂H₅NH₂

(vi) In increasing order of solubility in water:

C₆H₅NH₂, (C₂H₅)₂NH, C₂H₅NH₂.

p K_{b}

C_{2} H_{5} N H_{2}

C_{6} H_{5} N H C H_{3},

(C_{2} H_{5})_{2} N H

C_{6} H_{5} N H_{2}

C_{6} H_{5} N H_{2}, C_{2} H_{5} N H_{2}, (C_{2} H_{5})_{2} N H, N H_{3}

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