Question

# The correct order of bond angle in H2S, NH3, BF3 and SiH4 is :

A
H2S<NH3<SiH4<BF3
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B
NH3<H2S<SiH4<BF3
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C
H2S<SiH4<NH3<BF3
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D
H2S<NH3<BF3<SiH4
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Solution

## The correct option is A H2S<NH3<SiH4<BF3A) BF3 has trigonal planar geometry with 3 bond pairs. The bond angle is 120o.B) SiH4 is tetrahedral in shape with 4 bond pairs. The bond angle is 109.28o.C) NH3 is pyramidal in shape with 3 bond pairs and one lone pair. The bond angle is 107.5o.D) H2S is bent shaped with 2 bond pairs and two lone pairs. The bond angle is 92.3o. H2S92.3∘<NH3107.5∘<SiH4109∘28′<BF3120∘Hence, option A is correct.

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