Question

The correct order of bond angles among the following:

• A. $O{F}_2>H_{2}O$
• B. $OC{l}_2>OB{r}_2$
• C. $C{H}_4>N{H}_3$
• D. All of the above

Answer 1

The correct option is C $C{H}_4>N{H}_3$

a) Since fluorine is more electronegative than oxygen, the bond pairs are close to fluorine and hence there is minimum repulsion between and the bond pairs compared to $H_{2}O$ where the bond pairs are close to oxygen and hence, the bond angle of $O{F}_2$ is smaller than that of $O{H}_2$
b) Since $Br$ is larger than $Cl$ the bond angle of $OB{r}_2$ is larger than $OC{l}_2$
C) Since there are no lone pairs in methane, it will not have any distortion and hence a greater bond angle than $N{H}_3$