The correct order of decreasing bond lengths of CO, $C O_{2}$ and $C O_{3}^{2 -}$ is:

C O > C O_{2} > C O_{3}^{2 -}

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C O_{3}^{2 -} > C O_{2} > C O

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C O_{2} > C O > C O_{3}^{2 -}

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C O > C O_{3}^{2 -} > C O

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Solution

The correct option is B $C O_{3}^{2 -} > C O_{2} > C O$
Bond length is directly proportional to bond order and bond order depends on number of bonds
$∴ C O$ is $C \equiv O$
$C O_{2}$ is $O = C = O$
in $C O_{3}^{2 -}$ bond order lies between single and double bond due to resonance
Hence bond length order will be
$C O_{3}^{2 -} > C O_{2} > C O$

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