The correct order of dipole moment among the following:

I > I I > I I I

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I I > I > I I I

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I I I > I I > I

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I > I I I > I I

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Solution

The correct option is C $I I I > I I > I$
We know that the resultant dipole of two dipoles can be calculated as $\sqrt{μ_{1}^{2} + μ_{2}^{2} + 2 μ_{1} μ_{2} c o s θ}$
For I, $θ = 180^{o}$
The resultant dipole moment is zero, since $c o s 180^{o} = - 1$
Greter the value of $θ$ , smaller the resultant dipole moment
Hence the correct order is $I I I > I I > I$

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$C H_{3} B r, C H_{3} F, C H_{3} C l, C H_{3} I I, I I, I I I, I V$
The correct order of dipole moment will be:

E_{2}

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