The correct order of $E^{0} M^{2 +} / M$ values with negative sign for the four successive elements Cr, Mn, Fe and Co is

Fe ›Mn›Cr›Co

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Cr›Mn›Fe›Co

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Mn›Cr›Fe›Co

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Cr›Fe›Mn›Co.

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Solution

The correct option is C Mn›Cr›Fe›Co
$E^{0}$ values of $M^{2 +} / M$ with negative sign are: Cr=-0.91V, Mn= -1.18V, Fe=-0.44V,Co= -0.28V. Thus, the order is Mn $>$ Cr $>$ Fe $>$ Co.

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E_{M^{2 +} / M}^{0}

For the four successive transition elements (Cr, Mn, Fe and Co), what is the order of stability of their +2 states?

(At. Nos. Cr = 24, Mn = 25, Fe = 26, Co = 27)

E^{0} M^{2 +} / M

E_{M^{2 +} / M}^{o}

C r, M n, F e

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E_{M^{2 +} / M}

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