Question

The correct order of equivalent conductance at infinite dilution of $LiCl,NaCl$ and $KCl$ is :

• A. $LiCl>NaCl>KCl$
• B. $KCl>NaCl>LiCl$
• C. $NaCl>KCl>LiCl$
• D. $LiCl>KCl>NaCl$

Answer 1

Answer: (B)

$KCl>NaCl>LiCl$

Here, the anion is same in all the case, we just have to consider cation.

Cation whose charge density is more is hydrated by more molecules of water (solvation) which makes it immobile and thus decreases its conductance.

Charge density order: $K^{+}<N{a}^{+}<L{i}^{+}$.

Order of size of hydrated ion: $K^{+}<N{a}^{+}<L{i}^{+}$.

Order of mobility: $K^{+}>N{a}^{+}>L{i}^{+}$.

Hence, option B is correct.