Question

The correct order of following 3d metal oxides, according to their oxidation number is:
(a) $Cr{O}_3$
(b) $F{e}_2{O}_3$
(c) $Mn{O}_2$
(d) $V_2{O}_5$
(e) $C{u}_{2}O$

• A. $\left(a\right)>\left(d\right)>\left(c\right)>\left(b\right)>\left(e\right)$
• B. $\left(d\right)>\left(a\right)>\left(b\right)>\left(c\right)>\left(e\right)$
• C. $\left(a\right)>\left(c\right)>\left(d\right)>\left(b\right)>\left(e\right)$
• D. $\left(c\right)>\left(a\right)>\left(d\right)>\left(e\right)>\left(b\right)$

Answer 1

The correct option is A $\left(a\right)>\left(d\right)>\left(c\right)>\left(b\right)>\left(e\right)$

$\left(a\right)\stackrel{+6}{Cr}{O}_3$
$\left(b\right)\stackrel{+3}{F}{e}_2+3O_3$
$\left(c\right)\stackrel{+4}{Mn}{O}_2$
$\left(d\right)\stackrel{+5}{V_2}{O}_5$
$\left(e\right)\stackrel{+1}{C{u}_2}O$

So, the order of oxidation state is
$a>d>c>b>e$