The correct order of hydrogen bond strengths is:

C l H - - - C l > N H - - - N > O H - - - O > F H - - - F

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C l H - - - C l < N H - - - N < O H - - - O < F H - - - F

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C l H - - - C l < N H - - - N > O H - - - O > F H - - - F

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C l H - - - C l < N H - - - N < O H - - - O > F H - - - F

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Solution

The correct option is B $C l H - - - C l < N H - - - N < O H - - - O < F H - - - F$
$Strength of H-bond \propto polarity of H - atom \propto EN of the atom attach to the H - atom$
Higher the electronegativity of the element, higher will be the bond polarity of hydrogen.
Electronegative element withdraws the electron toward itself and create charge separation (polarity)
Electronegative order of the elements in given molecule is
F > O > N > Cl.
Thus strength of hydrogen bond is in the order,
$C l H . . . C l < N H . . . N < O H . . . O < F H . . . F$

Hence, the correct answer is option (b).

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Similar questions

Q. The increasing order of the strength of hydrogen bond in the following mentioned linkages is:
(i)

O H - S

(II)

S H - O

(iii)

F H - F

(iv)

F H - O

The increasing order of the strength of the hydrogen bond in the following mentioned linkages is:

(i) O H - S (i i) S H - O (i i i) F H - F (i v) F H - O

When Ba(OH)₂ is added to NH₄Cl then which of the following reactions is correct regarding the products formed:

Ba(OH)₂ + 2NH₄Cl ---------> BaCl₂ + 2NH₃+ 2H₂O

Ba(OH)₂+ 2NH₄Cl ----------> BaCl₂ + 2NH₄OH

Which of the following is not correct?

$O r d e r o f b a s i c i t y O r d e r o f n u c l e o p h i l i c i t y (a) F^{-} > C l^{-} > B r^{-} B r_{-} > C l^{-} > F^{-} (b) H - O - O^{-} > O H^{-} H - O - O^{-} > O H^{-} (c) C H_{3} > N H_{2}^{-} > O H - C H_{3} > N H_{2}^{-} > O H^{-} (d) H_{2} O > H_{2} S H_{2} O < H_{2} S$

$N H_{4} C l$ + $N a N O_{2} \to$ ____ + ____

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Periodic Properties

Standard XII Chemistry

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