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Question

The correct order of +I strength for the following groups
CH3,CH2R,CD3 is :
(Here R is any alkyl group ).


A
CH2R>CH3>CD3
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B
CH3>CD3>CH2R
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C
CD3>CH2R>CH3
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D
CH2R>CD3>CH3
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Solution

The correct option is D CH2R>CD3>CH3
Since alkyl group is an electron donating group :
More the number of alkyl groups attached more is the +I strength.
So, CH2R has the highest +I strength.
In case of isotopes, heavier isotopes show more +I effect.
Also, bond length of CD is less than CH bond length.
So electron density becomes higher due to shorter bond length.
+I effect is more for CD3
The correct order of decreasing +I strength is :
CH2R>CD3>CH3

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