The correct order of increasing bond angles is:

P F_{3} < P C l_{3} > P B r_{3} < P I_{3}

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P F_{3} < P B r_{3} < P C l_{3} < P I_{3}

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P I_{3} < P B r_{3} < P C l_{3} < P F_{3}

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P F_{3} < P C l_{3} < P B r_{3} < P I_{3}

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Solution

The correct option is D $P F_{3} < P C l_{3} < P B r_{3} < P I_{3}$
As the electronegativity of the bonded atom to the central metal atom decreases, its bond angle increases. Hence, bond angle will be maximum in $P I_{3}$ while it is minimum in $P F_{3}$

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