The correct order of increasing $C - O$ bond length of $C O, C O_{3}^{2 -} and C O_{2}$ is:

C O_{3}^{2 -} < C O_{2} < C O

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C O_{2} < C O_{3}^{2 -} < C O

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C O < C O_{3}^{2 -} < C O_{2}

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C O < C O_{2} < C O_{3}^{2 -}

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Solution

The correct option is D $C O < C O_{2} < C O_{3}^{2 -}$
Bond length $\propto \frac{1}{% π character}$
As can be seen from the structures of $C O, C O_{3}^{2 -} a n d C O_{2}$ , $π$ character is maximum in $C O$ and least in $C O_{3}^{2 -}$ . Hence, Bond length follows the order $C O < C O_{2} < C O_{3}^{2 -}$ .

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