The correct order of increasing ionic character is:

B e C l_{2} < M g C l_{2} < C a C l_{2} < B a C l_{2}

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B e C l_{2} < M g C l_{2} < B a C l_{2} < C a C l_{2}

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B e C l_{2} < B a C l_{2} < M g C l_{2} < C a C l_{2}

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B a C l_{2} < C a C l_{2} < M g C l_{2} < B e C l_{2}

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Solution

The correct option is A $B e C l_{2} < M g C l_{2} < C a C l_{2} < B a C l_{2}$
$C l$ is common in all the given molecules. As we go down in a group, electro-negativity decreases and tendency to form ionic compound increases. Hence, tendency to loose electrons also increases.
The order of increasing ionic character is: $B e C l_{2} < M g C l_{2} < C a C l_{2} < B a C l_{2}$ .

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