The correct order of increasing s character (in perencetage) in the hybrid orbitals in below molecules/ions is (assume all hybrid orbitals are exactly equivalent):
CO2−3I;XeF4II; I−3III; NCl3IV; BeCl2(g)V
Lesser is the number of p-orbitals more will be the percentage of s-character.
So the correct order of S-character in hybrid orbitals is sp>sp2>sp3>sp3d>sp3d2 . So the correct option is II<III<IV<I<V.
Hence option A is correct.