The correct order of matching of complex compound in column I with the properties in column II:
Column I Column II
A $[C r (N H_{3})_{6}]^{3 +}$ P Tetrahedral and paramagnetic
B $[C o (C N)_{6}]^{3 -}$ Q Octahedral and diamagnetic
C $[N i (C N)_{4}]^{3 -}$ R Octahedral and paramegnetic
D $[N i (C l)_{4}]^{2 -}$ S Square planar and diamagnetic

A-R; B - Q; C -P; D-S

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A-Q; B - R; C -P; D-S

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A-R; B - Q; C -S; D-P

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A-Q; B - R; C -S; D-P

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Solution

The correct option is B A-R; B - Q; C -P; D-S
(A) $A - R, B - Q, C - P, D - S$
because; A : Octahedral and paramagnetic as it has $6$ binding sirtes and contains unpaired electrons.
B: Octahedral and diamagnetic as it contains $6$ binding sites and electrons are paired.
C : Tetrahedral and paramagnetic contains $4$ electrons binding sides and unpaired electron.
D : It forms square planar and diamagnetic.

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	Column I		Column II
A	$[C r (N H_{3})_{6}]^{3 +}$	P	Tetrahedral and paramagnetic
B	$[C o (C N)_{6}]^{3 -}$	Q	Octahedral and diamagnetic
C	$[N i (C N)_{4}]^{3 -}$	R	Octahedral and paramegnetic
D	$[N i (C l)_{4}]^{2 -}$	S	Square planar and diamagnetic

The correct order of matching of complex compound in column I with the properties in column II:Column IColumn IIA[Cr(NH3)6]3+PTetrahedral and paramagneticB[Co(CN)6]3−QOctahedral and diamagneticC[Ni(CN)4]3−ROctahedral and paramegneticD[Ni(Cl)4]2−SSquare planar and diamagnetic