The correct order of reactivity of following compounds with PhMgBr will be.
(1) ${(C_{6} H_{5})}_{2} C O$
(2) ${C H}_{3} - C H = O$
(3) ${({C H}_{3})}_{2} C = O$

1 > 2 > 3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 > 3 > 1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

3 > 2 > 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1 > 3 > 2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $2 > 3 > 1$
Reactivity of grignard-reagents towards carbonyl compounds is high for aldehydes. Compared to ketones because of less steric hindrance in aldehydes.
Aldehyde(very less steric) $>$ Ketone(less steric) $>$ Ketone(high steric hindrance)
$C H_{3} - C H O > (C H_{3})_{2} C O > (C_{6} H_{5})_{2} C O$ [Reactivity]

Suggest Corrections

Similar questions

P h M g B r

(1) . (C_{6} H_{5})_{2} C O, (2) . C H_{3} - C H = O, (3) . (C H_{3})_{2} C = O

(1) C H_{3} C H_{2} C H_{2} C H_{2} O H

(2) C H_{3} C H_{2} C H_{2} C H O

(3) C H_{3} C H_{2} C H_{2} C O O H

C H_{3} C H_{2} C H_{2} C H_{2} O H

C H_{3} C H_{2} C H_{2} C H O

C H_{3} C H_{2} C H_{2} C O O H

Identify the correct order of boiling points of the following compounds.

C H_{3} (C H_{2})_{2} C H_{2} O H

C H_{3} (C H_{2})_{2} C H O

C H_{3} (C H_{2})_{2} C O O H

$\begin{matrix} C H_{3} O - C H = C H - N O_{2} & 1 C H_{2} = C H - N O_{2} & 2 C H_{2} = C H - C l & 3 C H_{2} = C H_{2} & 4 \end{matrix}$

Which of the following is the correct order of bond length among these compounds?

Join BYJU'S Learning Program