The correct order of the stoichiometries of $A g C l$ formed when $A g N O_{3}$ in excess is treated with the complexes: $C o C l_{3} .6 N H_{3}, C o C l_{3} .5 N H_{3}, C o C l_{3} .4 N H_{3}$ respectively is:

2 A g C l, 3 A g C l, 1 A g C l

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1 A g C l, 3 A g C l, 2 A g C l

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3 A g C l, 1 A g C l, 2 A g C l

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3 A g C l, 2 A g C l, 1 A g C l

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Solution

The correct option is C $3 A g C l, 2 A g C l, 1 A g C l$
The correct order of the stoichiometries of $A g C l$ formed is $3, 2, 1$ .
$C o C l_{3} .6 N H_{3} = [C o (N H_{3})_{6}] C l_{3}$

$[C o (N H_{3})_{6}] C l_{3} + 3 A g N O_{3} \to [C o (N H_{3})_{6}] (N O_{3})_{3} + 3 A g C l ↓$ .
$C o C l_{3} .5 N H_{3} = [C o (N H_{3})_{5} C l] C l_{2}$

$[C o (N H_{3})_{5} C l] C l_{2} + 2 A g N O_{3} \to [C o (N H_{3})_{5} C l] (N O_{3})_{2} + 2 A g C l ↓$ .
$C o C l_{3} .4 N H_{3} = [C o (N H_{3})_{4} C l_{2}] C l$

$[C o (N H_{3})_{4} C l_{2}] C l + A g N O_{3} \to [C o (N H_{3})_{4} C l_{2}] N O_{3} + A g C l ↓$ .

So, the correct option is $D$

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Similar questions

Q. The correct order of the stoichiometries of

A g C l

formed when

A g N O_{3}

in excess is treated with the complexes :

C o C l_{3} .6 N H_{3}, C o C l_{3} .5 N H_{3}, C o C l_{3} .4 N H_{3}

respectively is:

Th correct order of the stochiometrics of AgCl formed when $A g N O_{3}$ in excess is treated with the complexes: $C o C l_{3} .6 N H_{3}, C o C l_{3} .5 N H_{3}, C o C l_{3} .4 N H_{3}$ respectively is

Q. Which reaction is this?

C a C l_{2} + 2 A g N O_{3} \to 2 A g C l ↓ + C a (N O_{3})_{2}

Δ G^{\circ}

of the cell reaction,

A g C l (s) + \frac{1}{2} H_{2} (g) \to A g (s) + H^{+} + C l^{-} is - 21.52 K J . Δ G^{\circ} of 2 A g C l (s) + H_{2} (g) \to 2 A g (s) + 2 H^{+} 2 C l^{-}

is:

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The correct order of the stoichiometries of AgCl formed when AgNO3 in excess is treated with the complexes: CoCl3.6NH3,CoCl3.5NH3,CoCl3.4NH3 respectively is:

The correct order of the stoichiometries of $A g C l$ formed when $A g N O_{3}$ in excess is treated with the complexes: $C o C l_{3} .6 N H_{3}, C o C l_{3} .5 N H_{3}, C o C l_{3} .4 N H_{3}$ respectively is: