Question

The correct order towards bond angle is:

• A. ${sp}^3<{sp}^2<sp$
• B. $sp<{sp}^2<{sp}^3$
• C. $sp<{sp}^3<{sp}^2$
• D. ${sp}^2<{sp}^3<sp$

Answer 1

The correct option is A ${sp}^3<{sp}^2<sp$

For $sp$ hybridization, it has linear shape so ${180}^0$

For $s{p}^2$ hybridization, it has Trigonal geometry so ${120}^0$

For $s{p}^3$ hybridization, it has tetrahedral shape so ${109}^0$

Bond angles will be $s{p}^3<s{p}^2<sp$.