The correct relationship between the boiling points of very dilute solution of $A l C l_{3} (T_{1} K)$ and $C a C l_{2} (T_{2} K)$ having the same molar concentration is :

T_{1} = T_{2}

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T_{1} > T_{2}

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T_{2} > T_{1}

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T_{2} \leq T_{1}

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Solution

The correct option is A $T_{1} > T_{2}$
One molecule of $A l C l_{3}$ on ionization gives 4 particles.

One molecule of $C a C l_{2}$ on ionization gives 3 particles.

The molar concentration of the two solutions is the same.

The elevation in boiling point will be greater for $A l C l_{3}$ , as it gives more number of particles on ionization.

Hence, the boiling point of $A l C l_{3} (T_{1} K)$ is greater than the boiling point of $C a C l_{2} (T_{2} K)$ .

Thus, $T_{1} > T_{2}$ .

Hence, the correct option is $B$

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