The correct sequence of the decreasing order of reactivity during hydrolysis of acid chlorides is:

$P h C O C l > p - O_{2} N C_{6} H_{4} C O C l > p - C H_{3} O C_{6} H_{4} C O C l$

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$P h C O C l > p - C H_{3} O C_{6} H_{4} C O C l > p - O_{2} N C_{6} H_{4} C O C l$

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$p - O_{2} N C_{6} H_{4} C O C l > P h C O C l > p - C H_{3} O C_{6} H_{4} C O C l$

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$p - O_{2} N C_{6} H_{4} C O C l > p - C H_{3} O C_{6} H_{4} C O C l > P h C O C l$

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Solution

The correct option is C
$p - O_{2} N C_{6} H_{4} C O C l > P h C O C l > p - C H_{3} O C_{6} H_{4} C O C l$

Electron withdrawing group increases the rate while electron donating group decreases the rate of reactivity.

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S_{N} 1

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