The correct stability order for N 2 and its given ions is-A- N 2- N 2- N 2- N 22-B- N 2- N 2- N 2- N 22C- N 2- N 2- N 2- N 22-D- N 2- N 2- N 2- N 22-

The correct option is A N_2 gt;N^+_2 gt; N^ _2 gt;N^2 _2Use molecular orbital theory ...

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The correct stability order for $N_{2}$ and its given ions is:

N_{2} > N_{2}^{+} > N_{2}^{-} > N_{2}^{2 -}

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N_{2}^{-} > N_{2}^{+} > N_{2} > N_{2}^{2 -}

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N_{2}^{+} > N_{2}^{-} > N_{2} > N_{2}^{2 -}

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N_{2} > N_{2}^{+} = N_{2}^{-} > N_{2}^{2 -}

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lim n \to \infty [\frac{1}{n^{2}} {sec}^{2} \frac{1}{n^{2}} + \frac{2}{n^{2}} {sec}^{2} \frac{4}{n^{2}} + . . . . + \frac{1}{n} {sec}^{2} 1]

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