Question

The correct statement(s) about $C{r}^{2+}$ and $M{n}^{3+}$ is(are)
[Atomic numbers of $Cr=24$ and $Mn=25$]

• A. $C{r}^{2+}$ is a reducing agent
• B. $M{n}^{3+}$ is an oxidizing agent
• C. Both $C{r}^{2+}$ and $M{n}^{3+}$ exhibit $d^4$ electronic configuration
• D. When $C{r}^{2+}$ is used as a reducing agent, the chromium ion attains $d^5$ electronic configuration.

Answer 1

Answer: (A), (B), (C)

Both $C{r}^{2+}$ and $M{n}^{3+}$ exhibit $d^4$ electronic configuration

$C{r}^{2+}+M{n}^{3+}\rightleftharpoons C{r}^{3+}+M{n}^{2+}$

Here, $C{r}^{2+}$ is a reducing agent and $M{n}^{3+}$ is an oxidising agent. Both $C{r}^{2+}$ & $M{n}^{3+}$ have $d^4$ electronic configuration.