Question

The correct statements (s) about $C{r}^{2+}$ and $M{n}^{3+}$ is (are) [Atomic numbers of Cr = 24 and Mn = 25]

• A. $C{r}^{2+}$ is a reducing agent
• B. $M{n}^{3+}$ is an oxidizing agent
• C. Both $C{r}^{2+}$ and $M{n}^{3+}$ exhibit $d^4$ electronic configuration
• D. When $C{r}^{2+}$ is used as a reducing agent, the chromium ion attains $d^5$ electronic configuration.

Answer 1

Answer: (A), (B), (C)

The correct options are
A $C{r}^{2+}$ is a reducing agent
B $M{n}^{3+}$ is an oxidizing agent
C Both $C{r}^{2+}$ and $M{n}^{3+}$ exhibit $d^4$ electronic configuration

(a),(b), (c) $C{r}^{2+}$ is reducing agent and $M{n}^{3+}$ is an oxidation agent and both have electronic configuration $d^4$.
$E_{C{r}^{3+}/C{r}^{2+}}^{\circ }=-0.41V$ $E_{M{n}^{3+}/M{n}^{2+}}^{\circ }=1.5V$
Above $E^{\circ }$ value explains reducing nature of $C{r}^{2+}$ and oxidizing behavior of $M{n}^{3+}$.