Question

The corresponding altitudes of two similar triangles are 6 cm and 9 cm respectively find the ratio of their areas.

Answer 1

The ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding altitudes.

Hence the ratio of the areas$=\frac{(6{)}^2}{(9{)}^2}=\frac{36}{81}=\frac{4}{9}$

Hence the ratio of areas $=\frac{4}{9}$