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Standard IX

Mathematics

Framing Algebraic Equations

The cost of 3...

Question

The cost of 3 cricket bats and 6 balls is ₹ 3900. The cost of one bat and 3 balls of the same kind is ₹ 1700. Select the equations that represent this situation algebraically.

$x - 2 y = 1300$

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$x + 2 y = 1300$

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$3 x + 2 y = 1700$

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$x + 3 y = 1700$

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Solution

The correct options are
B
$x + 2 y = 1300$

D
$x + 3 y = 1700$

Let,
Cost of 1 cricket bat $=$ ₹ $x$
Cost of 1 cricket ball $=$ ₹ $y$

According to given conditions, we have
$3 x + 6 y = 3900$ , $x + 2 y = 1300$ and $x + 3 y = 1700$

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Similar questions

Q. The coach of a cricket team buys

3

bats and

6

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R s .3900

. Later, she buys another bat and

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R s . 1300

. Represent this situation algebraically.

Q. Question 2
The coach of a cricket team buys 3 bats and 6 balls for Rs 3900. Later, she buys another bat and 3 more balls of the same kind for Rs 1300. Represent this situation algebraically and geometrically.

Q. The coach of a cricket team buys

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c 1300.

Represent this situation algebraically and geometrically

The coach of a cricket team buys 3 bats and 6 balls for Rs 3900. Later, she buys another bat and 3 more balls of the same kind for Rs 1300. Represent this situation algebraically and geometrically.

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balls for

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. Later he buys another

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balls of the same kind for

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. Represent this situation algebraically and solve it by graphical method. Also, find out that how much money the coach will pay for the purchase of one bat and one ball.

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The cost of 3 cricket bats and 6 balls is ₹ 3900. The cost of one bat and 3 balls of the same kind is ₹ 1700. Select the equations that represent this situation algebraically.

The correct options are B x+2y=1300 D x+3y=1700 Let, Cost of 1 cricket bat = ₹ x Cost of 1 cricket ball = ₹ y According to given conditions, we have 3x+6y=3900, x+2y=1300 and x+3y=1700

The correct options are
B
$x + 2 y = 1300$

D
$x + 3 y = 1700$

Let,
Cost of 1 cricket bat $=$ ₹ $x$
Cost of 1 cricket ball $=$ ₹ $y$

According to given conditions, we have
$3 x + 6 y = 3900$ , $x + 2 y = 1300$ and $x + 3 y = 1700$