The cost of two red balls and five blue balls is ₹160. Then find the correct equation for this situation among the given options. (r:price of one red ball) (b:price of one blue ball)
A
2r+5b=₹160
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B
3r+5b=₹160
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C
r+5b=₹80
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D
2r−5b=₹160
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Solution
The correct option is A2r+5b=₹160
Given:
Cost of one Red ball = r.
Cost of one Blue ball = b.
So, the required algebraic equation will be 2r+5b=₹160