The counting rate observed from a radioactive source at t = 0 second was 1600 counts per second and at t = 8 seconds it was 100 counts per second. The counting rate observed as counts per second at t = 6 seconds will be
A
400
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B
300
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C
200
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D
150
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Solution
The correct option is C 200 By using A=A0(12)n⇒100=1600(12)8T1/2⇒116=(12)8T1/2⇒T1/2=2sec Again by using the same relation the count rate at t = 6 sec will be A=1600(12)62=200.