The cross-section of a cannel is a trapezium in shape. If the canal is 15 m wide at the top and 5 m wide at the bottom and the area of cross-section is 560 sq m, the depth of canal is:

14 m

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28 m

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56 m

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112 m

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Solution

The correct option is C 56 m
Area of a trapezium $= \frac{1}{2} \times$ (sum of parallel sides) $\times$ distance between them
$560 = \frac{1}{2} \times (15 + 5) \times d e p t h$
depth $= 56 m$

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The cross-section of a cannel is a trapezium in shape. If the canal is 15 m wide at the top and 5 m wide at the bottom and the area of cross-section is 560 sq m, the depth of canal is:

The correct option is C 56 m Area of a trapezium =12× (sum of parallel sides) × distance between them 560=12×(15+5)×depth depth =56m

The correct option is C 56 m
Area of a trapezium $= \frac{1}{2} \times$ (sum of parallel sides) $\times$ distance between them
$560 = \frac{1}{2} \times (15 + 5) \times d e p t h$
depth $= 56 m$