The cross section of a piece of metal of length 4 m is shown. If one cubic cm of the metal weighs 6.6 grams , find the approximate weight of the piece of metal

250 kg

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320 kg

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352 kg

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340 kg

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Solution

The correct option is C
352 kg

Area of the cross sections is - area of the rectangle ABEF + area of the triangle BCD.

= (12 x 10 ) + $\frac{1}{2}$ x (16 - 10)(12 - 7.5)

= 120 + $\frac{1}{2}$ x (6 x 4.5)

= 120 + 13.5

= 133.5 $c m^{2}$

Volume of cross section = area of cross section x length

= 133.5 x 400

= 53400 $c m^{3}$

weight of the metal in kgs = $\frac{6.6 \times 53400}{1000} = 352 k g (a p p r o x)$

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