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Crystal Field Split in Octahedral Complexes

The crystal f...

Question

The crystal field-splitting for $C r^{3 +}$ ion in octahedral field increases for ligands $I, H_{2} O, N H_{3}, C N^{-}$ and the order is :

I^{-} < H_{2} O < N H_{3} < C N^{-}

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C N^{-} < I^{-} < H_{2} O < N H_{3}

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C N^{-} < N H_{3} < H_{2} O < I^{-}

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N H_{3} < H_{2} O < I^{-} < C N^{-}

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Solution

The correct option is B $I^{-} < H_{2} O < N H_{3} < C N^{-}$
$I^{-} < B r^{-} < S^{2} - < S C N^{-} < C I^{-} < N O_{3}^{-}, F^{-} < O H^{-}$
$< E t O H < O X, < H_{2} O < N C S^{-} < p y, N H_{3} < e n < b p y, p h e n < N O_{2}^{-} < C_{6} H_{5}^{-} < C N^{-} < C O .$

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