The culturable command area for a distributed channel is 18,000 hectares. Wheat is grown in the entire area and the intensity of irrigation is 48%. The kor period for wheat is 30 days and the Kor water depth depth is 120 mm. The outlet discharge for the distributary should be

4 m^{3} / s

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4.63 m^{3} / s

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2 m^{3} / s

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2.85 m^{3} / s

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Solution

The correct option is A $4 m^{3} / s$
$Area to be irrigated = 18, 000 \times \frac{48}{100} = 8640 h a$

$Duty D = \frac{8.64 B}{D} = \frac{8.64 \times 30}{120 \times 10^{- 3}} = 2160 h a / c u m e c$

$Outlet discharge = \frac{Area to be irrigated}{Duty of crop}$

$= \frac{8640}{2160} = 4 c u m e c$

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The culturable command area for a distributed channel is 18,000 hectares. Wheat is grown in the entire area and the intensity of irrigation is 48%. The kor period for wheat is 30 days and the Kor water depth depth is 120 mm. The outlet discharge for the distributary should be

The correct option is A 4 m3/sArea to be irrigated=18,000×48100=8640 ha Duty D=8.64BD=8.64×30120×10−3=2160 ha/cumec Outlet discharge=Area to be irrigatedDuty of crop =86402160=4 cumec