Question

The culturable commanded area for a distributary is $3\times {10}^8{m}^2$. The intensity of irrigation for a crop is 42%. If kor water depth and Kor period for the crop are 12 cm and weeks, respectively. The peak demand discharge is:

• A. $4.63m^3/sec$
• B. $14.88m^3/sec$
• C. $12.50m^3/sec$
• D. $6.25m^3/sec$

Answer 1

The correct option is D $6.25m^3/sec$

Area to be irrigated = CCA x Intensity of irrigation

$=3\times {10}^8\times \frac{42}{100}=1.26\times {10}^8{m}^2$

Volume of water required by crop = area x Kor water depth

$=1.26\times {10}^8\times \frac{12}{100}=1.512\times {10}^7{m}^3$

$\therefore$ Peak demand discharge = $\frac{1.512\times {10}^7}{4\times 7\times 24\times 3600}=6.25m^3/sec$