The current gain for a transistor working as common base amplifier is $0.96$ . lf the emitter current is $7.2 m A$ , the base current will be :

0.42 m A

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0.49 m A

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0.29 m A

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0.35 m A

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Solution

The correct option is C $0.29 m A$
Here, $α = 0.96, I_{e} = 7.2 m A$
$\frac{I_{c}}{I_{e}} = 0.96$
$I_{c} = I_{e} \times 0.96 = 7.2 \times 0.96 = 6.912 m A$
Now,
$I_{b} = I_{c} - I_{c} = .2 - 6.912 = 0.29 m A$

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