The current I and voltage V graphs for a given metallic wire at two different temperatures T1 and T2 are shown in the figure. It is concluded that :
A
T1>T2
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B
T1<T2
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C
T1=T2
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D
T1=2T2
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Solution
The correct option is AT1>T2 Slope of the graph will give us reciprocal of resistance. Here resistance at temperature T1 is greater than that of R2. Since resistance of metallic wire is more at higher temperature than at lower temperature, hence T1>T2