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Electric Power

The current I...

Question

The current I and voltage V variations for a given metallic wire at two different temperatures $T_{1}$ and $T_{2}$ are shown in the figure. Then, which one of the following is correct?

T_{1} > T_{2}

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T_{1} = T_{2}

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T_{1} < T_{2}

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T_{1} = 2 T_{2}

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Solution

The correct option is C $T_{1} < T_{2}$
Slope of I Vs V graph gives the reciprocal of resistance and we know that resistance of metals increases with increase in temperature.
Thus we get from the graph that wire 2 has more resistance than wire 1 and so $T_{2} > T_{1}$ .

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The current I and voltage V variations for a given metallic wire at two different temperatures T1 and T2 are shown in the figure. Then, which one of the following is correct?

The correct option is C T1<T2Slope of I Vs V graph gives the reciprocal of resistance and we know that resistance of metals increases with increase in temperature.Thus we get from the graph that wire 2 has more resistance than wire 1 and so T2>T1.

The current I and voltage V variations for a given metallic wire at two different temperatures $T_{1}$ and $T_{2}$ are shown in the figure. Then, which one of the following is correct?

The correct option is C $T_{1} < T_{2}$
Slope of I Vs V graph gives the reciprocal of resistance and we know that resistance of metals increases with increase in temperature.
Thus we get from the graph that wire 2 has more resistance than wire 1 and so $T_{2} > T_{1}$ .