The current i in the circuit is

[IIT-JEE 1983]

1/45 A

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1/15 A

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1/10 A

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1/5 A

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Solution

The correct option is C
1/10 A

Apply KVL
Loop ABDE,
$+ 2 - 30 i_{1} = 0$
$i_{1} = \frac{1}{15} A \to (1)$

Loop ABCDE
$+ 2 - (i - i_{1}) 30 - (i - i_{1}) 30 = 0$
$i - i_{1} = \frac{1}{30}$

From (1)
$i = \frac{1}{30} + \frac{1}{15}$
$= \frac{1}{10} A$

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The current i in the circuit is [IIT-JEE 1983]

The correct option is C 1/10 A Apply KVL Loop ABDE, +2−30i1=0 i1=115A→(1) Loop ABCDE +2−(i−i1)30−(i−i1)30=0 i−i1=130 From (1) i=130+115 =110A

The current i in the circuit is

[IIT-JEE 1983]

The correct option is C
1/10 A

Apply KVL
Loop ABDE,
$+ 2 - 30 i_{1} = 0$
$i_{1} = \frac{1}{15} A \to (1)$

Loop ABCDE
$+ 2 - (i - i_{1}) 30 - (i - i_{1}) 30 = 0$
$i - i_{1} = \frac{1}{30}$

From (1)
$i = \frac{1}{30} + \frac{1}{15}$
$= \frac{1}{10} A$