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Question

The current I through a rod is given by I=0.2V1/2, where V is the potential difference across it. The rod is connected in series with a resistance across a 6V battery of negligible internal resistance. What is the value of resistance such that the power dissipated in the rod is three times that dissipated in the resistor?

A
5Ω
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B
3.535Ω
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C
1.0Ω
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D
2Ω
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Solution

The correct option is B 3.535Ω
6IR=V
I=0.2V1/2
Prod=6II2R=3I2R
IR=1.5
R=3.53

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